

The oxidation state of the vanadium is now +5.Įvery time you oxidise the vanadium by removing another electron from it, its oxidation state increases by 1.įairly obviously, if you start adding electrons again the oxidation state will fall. It is also possible to remove a fifth electron to give another ion (easily confused with the one before!). The positive oxidation state is counting the total number of electrons which have had to be removed - starting from the element. Notice that the oxidation state isn't simply counting the charge on the ion (that was true for the first two cases but not for this one). The vanadium is now in an oxidation state of +4. Removal of another electron gives a more unusual looking ion, VO 2+. The vanadium now has an oxidation state of +3. Removal of another electron gives the V 3+ ion: The vanadium is now said to be in an oxidation state of +2. If you think about how these might be produced from vanadium metal, the 2+ ion will be formed by oxidising the metal by removing two electrons:

Vanadium forms a number of different ions - for example, V 2+ and V 3+. If you don't know anything about vanadium, it doesn't matter in the slightest. We are going to look at some examples from vanadium chemistry. It would probably be best to read on and come back to these links if you feel you need to. Note: If you aren't sure about either of these things, you might want to look at the pages on redox definitions and electron-half-equations. Oxidation and reduction in terms of electron transfer However, for the purposes of this introduction, it would be helpful if you knew about: Oxidation states simplify the whole process of working out what is being oxidised and what is being reduced in redox reactions. Oxidation states are straightforward to work out and to use, but it is quite difficult to define what they are in any quick way.Įxplaining what oxidation states (oxidation numbers) are
#Oxidation number of chromium oxide how to#
This page explains what oxidation states (oxidation numbers) are and how to calculate them and make use of them.
